Aligner un bloc "numcases" à gauche

\documentclass[english, 10pt]{article}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage{lmodern}
\usepackage[a4paper, top=2cm, left=2cm, right=2cm, bottom=2cm]{geometry}

\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{amsthm}

\usepackage{mathtools}
\usepackage{stmaryrd}
\usepackage{tdsfrmath}
\usepackage{cases}
\usepackage{eqnarray}

\usepackage{babel}

    \begin{document}

    blablabla 
     %Nouvelle ligne
    \begin{numcases}{\text{or  \quad }}
        |\omega_2| < 1 \quad ; \quad |\omega_3| <1 \nonumber \\
        |\alpha_i|^2 \leq (1-|\omega_i|^2)(1-|\omega_{i+1}|^2), \; i=1,3 \nonumber \\
        |\alpha_2|^2 = (1-|\omega_2|^2)(1-|\omega_3|^2)  \nonumber \\
        \beta_i = \frac{-\alpha_i \alpha_{i+1} \omega_{i+1}}{1 - |\omega_{i+1}}, \; i=1,2 \nonumber \\
            \left| \gamma - \frac{\overline{\omega_2} \overline{\omega_3} \alpha_1 \alpha_2 \alpha_3}{(1-|\omega_2|^2)(1-|\omega_3|^2)} \right|^2 \leq  \left[1-|\omega_1|^2 - \frac{|\alpha_1|^2}{1-|\omega_2|^2} \right] \times \left[ 1-|\omega_4|^2 - \frac{|\alpha_3|^2}{1-|\omega_3|^2} \right] 
    \end{numcases}
    \end{document}